KOH和CH3COONH4及Ba(OH)2和NH4CL反应的化学方程式和离子方程式

问题描述:

KOH和CH3COONH4及Ba(OH)2和NH4CL反应的化学方程式和离子方程式

KOH+CH3COONH4====CH3COOK+NH3↑+H2O
OH- + NH4 ====NH3↑+H2O
Ba(OH)2+2NH4Cl==BaCl2+2NH3↑+2H2O
OH- + NH4+ ==NH3↑+H2O
CH3COONH4应是NH4CH3COO

KOH+CH3COONH4=KCH3COO+NH3↑+H2O
Ba(OH)2+2NH4Cl=BaCl2+2NH3↑+H2O

KOH+CH3COONH4====CH3COOK+NH3↑+H2O
OH- + NH4+====NH3↑+H2O
Ba(OH)2+2NH4Cl==BaCl2+2NH3↑+2H2O
OH- + NH4+ ==NH3↑+H2O

KOH+CH3COONH4=KCH3COO+NH3(↑)+H2O
Ba(OH)2+2NH4Cl=BaCl2+2NH3(↑)+H2O