(x-y)的2n+1次方-(x-z)(x-y)的2n次方+2(y-x)的2n次方(y-z)因式分解
问题描述:
(x-y)的2n+1次方-(x-z)(x-y)的2n次方+2(y-x)的2n次方(y-z)因式分解
答
(x-y)的2n+1次方-(x-z)(x-y)的2n次方+2(y-x)的2n次方(y-z)
=(x-y)的2n次方[(x-y)-(x-z)+2(y-z)]
=(x-y)的2n次方(x-y-x+z+2y-2z)
=(x-y)的2n次方(y-z)