(25/9)^0.5+(64/27)^(1/3)+lg6+√[(lg6)^2-lg36+1]
问题描述：
(25/9)^0.5+(64/27)^(1/3)+lg6+√[(lg6)^2-lg36+1]
答
(25/9)^0.5+(64/27)^(1/3)+lg6+√[(lg6)^2-lg36+1]
=(5/3)^2*0.5+(4/3)^3*1/3+lg6+√[(lg6)^2-2lg6+1]
=5/3+4/3+lg6+|lg6-1|
=3+lg6+1-lg6
=4.