6.用因式分解法解下列方程:(1)3x^2-12x=-12 (2)4x^2-144=0 (3) 3x(x-1)=2(x-1) (4)(2x-1)^2=(3-x)^2
问题描述:
6.用因式分解法解下列方程:(1)3x^2-12x=-12 (2)4x^2-144=0 (3) 3x(x-1)=2(x-1) (4)(2x-1)^2=(3-x)^2
答
3x^2-12x=-123x^2-12x+12=03 (x-2)^2=0x=2 或 x=24x^2-144=0 4x^2-144=04 (x-6) (x+6)x=-6 或 x=63x(x-1)=2(x-1)3x(x-1)-2(x-1)=0(x-1) (3 x-2)=0x=2/3 或 x=1(2x-1)^2=(3-x)^2(2x-1)^2-(3-x)^2=0(3 x-4) (x+2)=0 x=...