4x-3(x-5)=2x+(x-1) (3x+29)除以8=4x 7(x+10)=5(4x-10) 5分之2（x-15）+x=69
问题描述：
4x-3(x-5)=2x+(x-1) (3x+29)除以8=4x 7(x+10)=5(4x-10) 5分之2（x-15）+x=69
答
4x-3(x-5)=2x+(x-1) 4x-3x+15=2x+x-12x=16x=8(3x+29)除以8=4x3x+29=32x29x=29x=17(x+10)=5(4x-10) 7x+70=20x-5013x=120x=120/135分之2（x-15）+x=69 2/5x-6+x=691.4x=75x=375/7