化简求值 (x²/1+y²/1+xy/2﹚÷x²y²/x+y 当x+y-2013=0

问题描述:

化简求值 (x²/1+y²/1+xy/2﹚÷x²y²/x+y 当x+y-2013=0
(x²分之1+y²分之1+xy分之2﹚÷x²y²分之x+y

(x²分之1+y²分之1+xy分之2﹚÷x²y²分之x+y=(1/x+1/y)²×x²y²/(x+y)=(x+y)²/(x²y²)×x²y²/(x+y)=x+y;=2013;很高兴为您解答,skyhunter002为您答疑...