若(|x+1|+|x+2|)(|y-2|+|y+1|)(|z-3|+|z+1|)=36,则x+2y+3z的最大值是
问题描述:
若(|x+1|+|x+2|)(|y-2|+|y+1|)(|z-3|+|z+1|)=36,则x+2y+3z的最大值是
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答
若(|x+1|+|x-2|)(|y-2|+|y+1|)(|z-3|+|z+1|)=36,则x+2y+3z的最大值是______,最小值是_____.15;-6∵|X+1|+|X-2|≥3,|Y-2|+|Y+1|≥3,|Z-3|+|Z+1|≥4(|X+1|+|X-2|)(|Y-2|+|Y+1|)(|Z-3|+|Z+1|)≥3*3*4=36,∴|X+1|+|X-2|...