x²-64y²分之2x减x-8y分之1等于多少?请不要打"/"这个符号,我只要答案.

x²-64y²分之2x减x-8y分之1
=2x÷(x²-64y²)-1÷(x-8y)
=2x÷[(x+8y)*(x-8y)]-(x+8y)÷[(x-8y)*(x+8y)]
=(2x-x-8y)÷[(x-8y)*(x+8y)]
=(x-8y)÷[(x-8y)*(x+8y)]
=1÷(x+8y)
=x+8y分之1