电阻R1=6Ω和R2=12Ω并联在电路中,测得R1消耗的电功率是6瓦,求(1)R1两端的电压是多少?

问题描述:

电阻R1=6Ω和R2=12Ω并联在电路中,测得R1消耗的电功率是6瓦,求(1)R1两端的电压是多少?
(2)R1和R2消耗的总功率是多少?

U^2/R1=6 所以U=6V (RI两端的电压为6V) P2=U^2/R2=36/12=3W 所以(R1和R2消耗的总功率是多少)P总=P1+P2=6+3=9W