1/3[3y-(10-7y/2)]-1/6[2y-(2y+2/3)]=y/2-1要过程

问题描述:

1/3[3y-(10-7y/2)]-1/6[2y-(2y+2/3)]=y/2-1要过程

Y-10/3+7/6Y-1/3Y+1/3Y+1/9=1/2Y-1
Y=10/9