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[(1-2i)^2/(3-4i)]-[(2+i)^2/(4-3i)]=?

分类: 作业答案 • 2021-12-28 11:25:37
问题描述：

[(1-2i)^2/(3-4i)]-[(2+i)^2/(4-3i)]=?

答

[(1-2i)^2/(3-4i)]-[(2+i)^2/(4-3i)]
=[1-4-4i)/(3-4i)]-[(4-1+4i)/(4-3i)]
=-(3+4i)/(3-4i)-(3+4i)/(4-3i)
=-(3+4i)^2/[(3-4i)(3+4i)]-(3+4i)(4+3i)/[(4-3i)(4+3i)]
=-(9-16+24i)/(9+16)-(12+9i+16i-12)/(16+9)
=(7-24i)/25-(25i)/25
=7/25-24/25i-i
=7/25-49/25i

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