x三次方+6x平方+11x+6=0
问题描述：
x三次方+6x平方+11x+6=0
答
x^3+6x^2+11x+6=0
==>(x^3+6x^2+5x)+(6x+6)=0
==>x(x^2+6x+5)+6(x+1)=0
==>x(x+1)(x+5)+6(x+1)=0
==>(x+1)(x(x+5)+6)=0
==>(x+1)(x^2+5x+6)=0
==>(x+1)(x+2)(x+3)=0
==>x=-1或x=-2或x=-3
答
x的立方+6x的平方+9x+2x+6=0
(x+1)(x+2)(x+3)=0
x=-1或-2或-3
答
x=-1时成立
所以有因式x+1
x³+x²+5x²+11x+6=0
x²(x+1)+(5x+6)(x+1)=0
(x+1)(x²+5x+6)=0
(x+1)(x+2)(x+3)=0
x=-1,x=-2,x=-3
答
-1 or -2 or -3
答
x^3+6x^2+11x+6=0
(x^3+6x^2+9x)+(2x+6)=0
x(x^2+6x+9)+2(x+3)=0
x(x+3)^2+2(x+3)=0
(x+3)[x(x+3)+2]=0
(x+3)(x+2)(x+1)=0
x+3=0 x1=-3
x+2=0 x2=-2
x+1=0 x3=-1
答
X=-3