AA*BB=CAAC,DD*EE=DFFD,BB*BB=AAFF求A+B+C+D+E+F
问题描述:
AA*BB=CAAC,DD*EE=DFFD,BB*BB=AAFF求A+B+C+D+E+F
答
AA*BB=CAAC
77*88=6776
DD*EE=DFFD
55*99=5445
BB*BB=AAFF
88*88=7744
A+B+C+D+E+F
=39
答
由BB×BB = AAFF 推理B×B×11×11 = 11×A0F因此A0F = B的平方×11A0F能被11整除,商是一个完全平方数,且A + F = 11 .一位数字的平方×11=某0某 的只有64×11 = 704A = 7,F = 4,B = 8再由AA*BB=CAAC即77×88 = 6776...