含0.6molAl3+的Al2(SO4)3中所含的SO42-物质的量是_.

问题描述:

含0.6molAl3+的Al2(SO43中所含的SO42-物质的量是______.

Al2(SO43中n(Al3+):n(SO42-)=2:3,
n(Al3+)=0.6mol,
则n(SO42-)=0.6mol×

3
2
=0.9mol,
故答案为:0.9mol.