用因式分解法解下列二元一次方程①3X²+2X=0②X(3X+2)-6(3X+2)=0③9t-(t-1)²=0
问题描述：
用因式分解法解下列二元一次方程①3X²+2X=0②X(3X+2)-6(3X+2)=0③9t-(t-1)²=0
④（2X+3）²=（X-1）²
答
①3X²+2X=0x(3x+2)=0x=0或者3x+2=0x=-2/3②X(3X+2)-6(3X+2)=0(3x+2)(x-6)=03x+2=0x=-2/3或者x-6=0x=6③9t²-(t-1)²=0(3t+t-1)(3t-t+1)=0(4t-1)(2t+1)=04t-1=0t=1/4或者2t+1=0t=-1/2④（2X+3）²=...