解方程组:√2x+√3y=3√2,√3x+√2y=2√3

问题描述:

解方程组:√2x+√3y=3√2,√3x+√2y=2√3


√2x+√3y=3√2 ①
√3x+√2y=2√3 ②
①×√3得:
√6x+3y=3√6 ③
②×√2得:
√6x+2y=2√6 ④
③-④得;
y=√6
∴x=0