解方程组:√2x+√3y=3√2,√3x+√2y=2√3
问题描述:
解方程组:√2x+√3y=3√2,√3x+√2y=2√3
答
解
√2x+√3y=3√2 ①
√3x+√2y=2√3 ②
①×√3得:
√6x+3y=3√6 ③
②×√2得:
√6x+2y=2√6 ④
③-④得;
y=√6
∴x=0