3/5+3(x-1/2003)=4/5 则代数式7+30(x-1/2003)的值是

问题描述:

3/5+3(x-1/2003)=4/5 则代数式7+30(x-1/2003)的值是

3/5+3(x-1/2003)=4/5
所以3(x-1/2003)=4/5-3/5
3(x-1/2003)=1/5
两边乘10
30(x-1/2003)=2
同时加上7
7+30(x-1/2003)=7+2=9