a+b/ab-b+c/bc和(1+ 3/x-1 )/ x+2/x平方-1 2/x+1=1/2x-1和5m-4/2m-4=2m+5/3m-6-1/2

a+b/ab-b+c/bc= a+1/a - b + 1/b= a+1/a[1+ 3/(x-1) ] / [(x+2) / (x²-1)]= [(x+2) /(x-1) ] /{(x+2) / [(x+1) (x-1)]}= x+12/x+1=1/2x-1(2+x)/x = (1-2x)/2x2+x = (1-2x)/24+2x = 1-2x4x = -3x = -3/45m-4/2m-...(5m-4/2m-4)=(2m+5/3m-6)-1/2括号加的可能还是不对？你看一下，是不是下面这样的？(5m-4)/(2m-4) = (2m+5)/(3m-6)-1/2现按这个式子就解如下：(5m-4)/(2m-4) = (2m+5)/(3m-6)-1/2(5m-4)/[2(m-2)] = (2m+5)/[3(m-2) - 1/2两边同乘以 6(m-2) 得3(5m-4) = 2(2m+5) - 3(m-2)15m-12 = 4m + 10 - 3m +614m =28m =2明天再见！