用递等式计算. 68×35-408÷24 8/49÷[9/8-(1/8+3/7)] 18-10.4÷(6.2-4.9)
问题描述:
用递等式计算.
68×35-408÷24 |
|
18-10.4÷(6.2-4.9) |
答
(1)68×35-408÷24,
=2380-17,
=2363;
(2)
÷[8 49
-(9 8
+1 8
)],3 7
=
÷[8 49
-9 8
-1 8
],3 7
=
÷[1-8 49
],3 7
=
×8 49
,7 4
=
;2 7
(3)18-10.4÷(6.2-4.9),
=18-10.4÷1.3,
=18-8,
=10.