用分解因式法解这几个方程(x+1)^2=2x(x+1),(x-3)(x+1)=-4,(x-4)^2-9=0,x^2-8x=16=0.
问题描述：
用分解因式法解这几个方程(x+1)^2=2x(x+1),(x-3)(x+1)=-4,(x-4)^2-9=0,x^2-8x=16=0.
答
(x+1)^2=2x(x+1)(x+1)^2-2x(x+1)=0(x+1)(x+1-2x)=0(x+1)(1-x)=0x+1=0 or 1-x=0x1=-1,x2=1.(x-3)(x+1)=-4x^2-2x-3=-4x^2-2x+1=0(x-1)=0x1=x2=1.(x-4)^2-9=0(x-4+3)(x-4-3)=0(x-1)(x-7)=0x-1=0 or x-7=0x1=1,x2=7.x^2-...