[(√2-1)∧2009]*[(√2+1)∧2010]怎么化简
问题描述:
[(√2-1)∧2009]*[(√2+1)∧2010]怎么化简
答
(√2-1)^2009][(√2+1)^2010]
={[(√2-1)(√2+1)]^2009}(√2+1)
=√2+1
答
[(√2-1)^2009][(√2+1)^2010]
={[(√2-1)(√2+1)]^2009}(√2+1)
=√2+1