[(√2-1)∧2009]*[(√2+1)∧2010]怎么化简

问题描述:

[(√2-1)∧2009]*[(√2+1)∧2010]怎么化简

(√2-1)^2009][(√2+1)^2010]
={[(√2-1)(√2+1)]^2009}(√2+1)
=√2+1

[(√2-1)^2009][(√2+1)^2010]
={[(√2-1)(√2+1)]^2009}(√2+1)
=√2+1