化简(根号6+根号3+2+根号2)除以(2根号2+根号3+1)
问题描述:
化简(根号6+根号3+2+根号2)除以(2根号2+根号3+1)
答
(√6+√3+2+√2) / (2√2+√3+1)
=(√3+1)/2
答
(根号6+根号3+2+根号2)除以(2根号2+根号3+1)=[根号3*(根号2+1)+根号2*(根号2+1)]÷(2根号2+根号3+1)=(根号3+根号2)*(根号2+1)÷【(根号3+根号2) +(根号2+1)】=1÷【1/(根号2+1) + 1/(根号3+根号2)...