一个减法算式,被减数,减数,差这三个数的和是41分之36．已知减数相当于被减数的9分之2,被减?减数?差要算式啊,快,好的追分.快在一个减法算式中,被减数,减数,差这三个数的和是41分之36．已知减数相当于被减数的9分之2,那么被减数是?减数是?差是?

36/41/(9×2)=2/41
被减数=2/41×9=18/41
减数=18/41×2/9=4/41
差=18/41-4/41=14/41

被减数是x,减数就是2/9 x ,差就是7/9 x
2x=36/41 解得x=18/41
减数是2/9 *18/41 =4/41
差是18/41 -4/41 =14/41

a - b = c
a + b + c = 36/41
b = 2a/9
a - 2a/9 = 7a/9
c = 7a/9
a + 2a/9 + 7a/9 = 36/41
a = 18/41
b = 4/41
c = 14/41
或：被减数是x,减数就是2/9 x ,差就是7/9 x
2x=36/41 解得x=18/41
减数是2/9 *18/41 =4/41
差是18/41 -4/41 =14/41

设被加数为x，减数为y，差就是x-y
x+y+（x-y）=36/41
y/x=2/9
解得x=18/41,y=4/41,x-y=14/41

a - b = c
a + b + c = 36/41
b = 2a/9
a - 2a/9 = 7a/9
c = 7a/9
a + 2a/9 + 7a/9 = 36/41
a = 18/41
b = 4/41
c = 14/41