求解初中数学题（x-y)-2(y-x) 2(x-y)-8(y-x) x(a-3)-(3-a) (x2-y2)-3(x+y)求解因式分解法.八年级数学.谢

检查一下题

（x-y)-2(y-x) 2(x-y)-8(y-x) x(a-3)-(3-a) (x2-y2)-3(x+y)
=(x-y)+4(x-y)²+8x(x-y)(a-3)+2(a-3)(x-y)-3(x+y)
=(x-y) [1-4(x-y)] + (a-3) (x-y) (8x+2) -3(x+y)
=(x-y)[1-4(x-y)+(a-3)(8x+2)]-3(x+y)
应该就是这样了，哈哈

1.
=(x-y)+2(x-y)
=3(x-y)
=3x-3y
2.
=2(x-y)+8(x-y)
=10(x-y)
=10x-10y
3.
=x(a-3)+(a-3)
=(a-3)(x+1)
4.
=(x+y)(x-y)-3(x+y)
=(x+y)(x-y-3)

1.
（x-y)-2(y-x)
=(x-y)+2(x-y)
=3(x-y)
2.
2(x-y)-8(y-x)
=2(x-y)+8(x-y)
=10(x-y)
3.
x(a-3)-(3-a)
=x(a-3)+(a-3)
=(a-3)(x+1)
4.
(x2-y2)-3(x+y)
=(x+y)(x-y)-3(x+y)
=(x+y)(x-y-3)

（x-y)-2(y-x) =(x-y)+2(x-y)=3(x-y)=3x-3y2(x-y)-8(y-x) =2(x-y)+8(x-y)=10(x-y)=10x-10yx(a-3)-(3-a) =x(a-3)+(a-3)=(a-3)(x+1)(x2-y2)-3(x+y)=(x+y)(x-y)-3(x+y)=(x+y)(x-y-3)