谢谢,请快一点! (2x^2-18)/(4-4x+x^2)/[(x+3)*(3-x)/(x^2-2x-3)]

问题描述:

谢谢,请快一点! (2x^2-18)/(4-4x+x^2)/[(x+3)*(3-x)/(x^2-2x-3)]

(2x^2-18)/(4-4x+x^2)/[(x+3)*(3-x)/(x^2-2x-3)]
=2(x+3)(x-3)/(x-2)^2*(x-3)(x+1)/(x+3)(3-x)
=-2(x-3)(x+1)/(x-2)^2