﹙3a³-5²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2

问题描述:

﹙3a³-5²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2

题目应是 ﹙3a³-a²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2
=-9a+3-3a²+2a
=-3a²-7a+3