化简(2-1)(2+1)(2^2+1)(2^4+1)...(2^32+1)+1 请指出化简结果的末位数字
问题描述：
化简(2-1)(2+1)(2^2+1)(2^4+1)...(2^32+1)+1 请指出化简结果的末位数字
提示：2^1=2,2^2=4,2^3=8,2^4=16,2^5=32,2^6=64,.
算式已经知道答案了,只要指出化简结果的末位数字就行了.快,
答
(2-1)(2+1)(2^2+1)(2^4+1)...(2^32+1)+1
=(2^2-1)(2^2+1)(2^4+1)...(2^32+1)+1
=(2^4-1)(2^4+1)...(2^32+1)+1
=(2^8-1)...(2^32+1)+1
……………………………………………………
=2^32-1+1
=2^32
化简结果的末位数字4算式结果不是等于2^64？(2-1)(2+1)(2^2+1)(2^4+1)...(2^32+1)+1 =(2^2-1)(2^2+1)(2^4+1)...(2^32+1)+1 =(2^4-1)(2^4+1)...(2^32+1)+1 =(2^8-1)...(2^32+1)+1 ……………………………………………………=2^64-1+1 =2^64化简结果的末位数字6是的，最后马虎了