常微分[e(x+y)的次方-e的x次方]dx+{e(x+y)的次方+e的y次}dy=0通解

问题描述:

常微分[e(x+y)的次方-e的x次方]dx+{e(x+y)的次方+e的y次}dy=0通解

e^(x+y)-e^x+e^y=c