(2a-3)(3a+1)-6a(a-4),其中a=2
问题描述:
(2a-3)(3a+1)-6a(a-4),其中a=2
答
:(2a-3)(3a+1)-6a(a-4) =6a+2a-9a-3-6a+24a=17a-3 ∴当a=2时,17a-3=17×2-3=31
(2a-3)(3a+1)-6a(a-4),其中a=2
:(2a-3)(3a+1)-6a(a-4) =6a+2a-9a-3-6a+24a=17a-3 ∴当a=2时,17a-3=17×2-3=31