计算:999的三次方+3乘999的平方+3乘999+1

问题描述:

计算:999的三次方+3乘999的平方+3乘999+1

令a=999
则原式=a³+3a²+3a+1
=a³+a²+2a²+3a+1
=a²(a+1)+(2a+1)(a+1)
=(a+1)(a²+2a+1)
=(a+1)³
=1000³
=1000000000