问道题目初高中衔接因式分解x三次方+3x二次方+3x+2x四次方-7x二次方+9不要只是一个结果= =泪奔了...

1、
原式=x³+3x²+3x+1+1
=(x³+1)+3x²+3x+1
=(x+1)(x²-x+1)+3x(x+1)+1
=(x+1)(x²-x+1+3x)+1
=(x+1)(x²+2x+1)+1
=(x+1)³+1³
=(x+1+1)[(x+1)²-(x+1)+1]
=(x+2)(x²+x+1)
2、
原式=(x^4-6x²+9)-x²
=(x²-3)²-x²
=(x²+x-3)(x²-x-3)

x^3+3x^2+3x+2
=x^3+2x^2+x^2+2x+x+2
=x^2(x+2)+x(x+2)(+(x+2)
=(x+2)(x^2+x+1)
x^4-7x^2+9
=x^2-6x^2+9-x^2
=(x^2-3)^2-x^2
=(x^2+x-3)(x^2-x-3)

x三次方+3x二次方+3x+2
=x^3+3x^2+3x+2
=(x^3+3x^2+2x)+(x+2)
=x(x+1)(x+2)+(x+2)
=(x^2+x+1)(x+2)
x四次方-7x二次方+9
令x^2=t
t^2-7t+9
=[t-(7-√13)/2]*[t-(7+√13)/2]