运用分式的加减(二)计算 (x/x+y+2y/x+y)*xy/x+2y÷(1/x+1/y)

问题描述:

运用分式的加减(二)计算 (x/x+y+2y/x+y)*xy/x+2y÷(1/x+1/y)
(1)(x/x+y+2y/x+y)*xy/x+2y÷(1/x+1/y) (2) (1/a+1/b)²÷(1/a²-1/b²) (3) (3x²/4y)² * 2y/3x+x²/2y²÷2y²/x (4) (a+b/a-b)² * 2a-2b/3a+3b-a²/a²-b²÷a/b

学习主要靠自己!(1)原式=(x+2y)/(x+y)*xy/(x+2y)÷(x+y)/xy=xy/(x+y)*xy/(x+y)=x^2y^2/(x^2+2xy+Y^2 (2)原式=[(a+b)/ab]^2÷(b^2-a^2)/a^2b^2=(a+b)^2/a^2b^2*a^2b^2/[(a+b)(b-a)]=(a+b)/(b-a)(3)原式=9x^4/16y^...