1/x+1-x+3/x^2-1除以x^2+4x+3/x^2-2x+1,其中x=-1/2
问题描述:
1/x+1-x+3/x^2-1除以x^2+4x+3/x^2-2x+1,其中x=-1/2
答
=[(x-1)-(x+3)]/(x+1)(x-1) ×(x-1)^2/(x+3)(x+1)
=-4(x-1)/(x+1)^2(x+3)可以再详细点吗?谢谢已经详细了呀