3(x+y)的平方-7(x+y)+8(x+y)的平方+6(x+y)-11(x+y)的平方=?

问题描述:

3(x+y)的平方-7(x+y)+8(x+y)的平方+6(x+y)-11(x+y)的平方=?

你没抄错题?!这是问题吗?直接以合并等于-x-y


3(x+y)²-7(x+y)+8(x+y)²+6(x+y)-11(x+y)²
=(3+8-11)(x+y)²+(6-7)(x+y)
=-(x+y)
=-x-y

答:
3(x+y)²-7(x+y)+8(x+y)²+6(x+y)-11(x+y)²
=(3+8-11)(x+y)²+(6-7)(x+y)
=0-(x+y)
=-x-y