解下列方程组:a+b+c=-6,a-b+c-8,4a+2b+c=-11(2)3x-y+z=42x+3y-2z=123x+2y=66(3)2x-5y=-117y+4z=55x+2z=2(4)x+y+z=-12x-y-z=1x-2y+z=-4
问题描述:
解下列方程组:a+b+c=-6,a-b+c-8,4a+2b+c=-11
(2)3x-y+z=4
2x+3y-2z=12
3x+2y=66
(3)2x-5y=-11
7y+4z=5
5x+2z=2
(4)x+y+z=-1
2x-y-z=1
x-2y+z=-4
答