计算(1-2i)-(2-3i)+(3-4i)-····+(2101-2102i)-(2102-2103i)
问题描述:
计算(1-2i)-(2-3i)+(3-4i)-····+(2101-2102i)-(2102-2103i)
答
原式=[(1-2)+(3-4)+…+(2101-2102)]+[(-2+3)+(-4+5)+…+(-2102+2103)]i
=-2102/2+(2102/2)i
=-1051+1051i