计算（lg8+lg1000)*lg5+3(lg2)+lg6（负一次方）+lg0.006

分类: 作业答案 • 2021-12-20 05:59:39

问题描述：

答

=（3lg2+3lg10)lg5+3(lg2)^2-lg6+lg6-3lg1 =(3lg2+3lg2+3lg5)lg5+3(lg2)^2 =6lg2lg5+3(lg5)^2+3(lg2)^2 =3 ( (lg2)^2+2lg2lg5+(lg2)^2 ) =3 (lg2+lg5)^2 =3