9ab ²+6abc/3ab 9a²+6ab+b²/3a+b x²-36/2x+12 这些分式约分怎么约?
问题描述:
9ab ²+6abc/3ab 9a²+6ab+b²/3a+b x²-36/2x+12 这些分式约分怎么约?
答
9ab ²+6abc/3ab
=3ab(3b+2c)/3ab
=3b+2c
9a²+6ab+b²/3a+b
=(3a)²+2*3a*b+b²/3a+b
=(3a+b)²/3a+b
=3a+b
x²-36/2x+12
=(x+6)(x-6)/2(x+6)
=x-6/2
答
9ab ²+6abc/3ab
=3ab(3b+2c)/3ab
=3b+2c
9a²+6ab+b²/3a+b
=(3a+b)²/(3a+b)
=3a+b
x²-36/2x+12
=(x-6)(x+6)/2(x+6)
=(x-6)/2