(3.7+5又2/3-1又2/3)÷0.11×0.037.2×7/6+5/6×7.2-7.2×22500÷2003/200425又1/3-[(22-19.75)-(17.25-16又1/3)]简便运算,
问题描述:
(3.7+5又2/3-1又2/3)÷0.11×0.03
7.2×7/6+5/6×7.2-7.2×2
2500÷2003/2004
25又1/3-[(22-19.75)-(17.25-16又1/3)]
简便运算,
答
(3.7+5又2/3-1又2/3)÷0.11×0.03=(3.7+4)/0.11*0.03=7.7/0.11*0.03=2.1
7.2×7/6+5/6×7.2-7.2×2=7.2*(7/6+5/6-2)=0
25又1/3-[(22-19.75)-(17.25-16又1/3)]=25又1/3-[(22+16又1/3)-(19.75+17.25)]=25又1/3-(22+16又1/3-37)=(25又1/3-16又1/3)+15=24
答
(3.7+5又2/3-1又2/3)÷0.11×0.03
=(3.7+4)÷0.11×0.03
=7.7÷0.11×0.03
=70×0.03
=2.1
7.2×7/6+5/6×7.2-7.2×2
=7.2×(7/6+5/6-2)
=7.2×0
=0
2500÷2003/2004
=2500×2004/2003
=2500×(1+1/2003)
=2500+2500/2003
=2501又497/2003
25又1/3-[(22-19.75)-(17.25-16又1/3)]
=25又1/3-[22-19.75-(17.25-16又1/3]
=25又1/3-22+19.75+17.25-16又1/3
=9-22+37
=24