若代数式3(2y-3)-y的值与-7(1-y)互为相反数,求y的值

【3(2y-3)-y】-【-7(1-y)】=0
因为3(2y-3)-y=0，-7(1-y)=0
所以3(2y-3)-y+(-7(1-y))=0
6y-9-y-7+7y=0
12y=16
y=4/3
最后得出的结果等于4/3.

∵ 3(2y-3)-y=-7(1-y) 3(2y-3)-y=7(1-y) 6y-9-y=7-7y 6y-y+7y=7+9 12y=16 y=4/3（3分之4） ∴ 相反数是3(2y-3)-y=7(1-y) 你读那个学校？？？？

3(2y-3)-y-7(1-y)＝0
6y-9-y-7+7y=0
12y-16=0
y=4/3

代数式3(2y-3)-y的值与-7(1-y)互为相反数
3(2y-3)-y+(-7(1-y))=0
6y-9-y-7+7y=0
12y=16
y=4/3

-3(2y-3)-y=-7(1-y)
3(2y-3)-y=7(1-y)
6y-9-y=7-7y
12y=16
y=16/12=4/3

3(2y-3)-y+[-7(1-y)]=0,6y-9-y-7+7y=0,12y=9,y=3/4

3(2y-3)-y的值与-7(1-y)互为相反数
3(2y-3)-y+[-7(1-y)]=0
6y-9-y-7(1-y)=0
6y-9-y-7+7y=0
6y+7y-y-9-7=0
12y-16=0
3y-4=0
3y=4
y=4/3

3(2y-3)-y的值与-7(1-y)互为相反数
则3(2y-3)-y+[-7(1-y)]=0
6y-9-y-7+7y=0
12y=16
y=16÷12
y=3分之4