Sodium with 4.6g is reacting with HCl with 3.65g.How many grams of gas can we collect?When sodium is reacting with acid liquor,if sodium is excessive in amount,please watch out for the reaction of sodium and water

问题描述:

Sodium with 4.6g is reacting with HCl with 3.65g.How many grams of gas can we collect?When sodium is reacting with acid liquor,if sodium is excessive in amount,please watch out for the reaction of sodium and water

4.6g钠与 3.65g.克盐酸的多少气体可以收集?如钠量过多,请留意钠与水反应
反应方程式:Na + 2HCl = 2NaCl + H2↑2Na + 2H2O = 2NaOH + H2↑Na + 2HCl = 2NaCl + H2↑23 2*36.5 2m 3.65g x23/m = 2*36.5/3.65 =2/x;m=1.15g x=0.1g与酸反应后钠剩余:4.6-1.15=3.45g2Na + 2H2O = 2NaOH + H2↑23*2 23.45g y 23*2/3.45=2/y y=0.15*生氢气总质量为:x+y=0.1+0.15=0.25g
总量(注意,mol!)为0.25g / 2g/mol =0.125 mol!

可收集0.25gH2;与水继续反应,而且特别剧烈,放出大量气体。

在酸液中,4.6g钠与3.65g氯化氢反应,钠是否过量,一共可以产生多少气体,并写出钠与水的反应.
反应方程式:
Na + 2HCl = 2NaCl + H2(g)
2Na + 2H2O = 2NaOH + H2(g)
Na + 2HCl = 2NaCl + H2(g)
23 2*36.5 2
m0 3.65g x
23/m0 = 2*36.5/3.65 =2/x;
m0=1.15g
x=0.1g
与酸反应后钠剩余:4.6-1.15=3.45g
与水继续反映的钠为:
2Na + 2H2O = 2NaOH + H2(g)
23*2 2
3.45g y
23*2/3.45=2/y
y=0.15g
产生氢气总量为:
x+y=0.1+0.15=0.25g