1又(1/4)-(9/20)+(11/30)-(13/42)+(15/56)-(17/72)+(19/90)等于几

问题描述:

1又(1/4)-(9/20)+(11/30)-(13/42)+(15/56)-(17/72)+(19/90)等于几

1又(1/4)-(9/20)+(11/30)-(13/42)+(15/56)-(17/72)+(19/90)=1又1/10