1.(x-y)³·(x+y)²·【(x-y)³】²·【(-x-y)³】的六次方

问题描述:

1.(x-y)³·(x+y)²·【(x-y)³】²·【(-x-y)³】的六次方

原式=(x-y)³·(x+y)²·(x-y)的六次方·【-(x+y)³】的六次方
=(x-y)的9次方·(x+y)²(x+y)的18次方
=(x-y)的9次方·(x+y)的20次方