(1/2x+2/3x-3/4x)^2-(1/2x-2/3x-3/4x)^2=?
问题描述:
(1/2x+2/3x-3/4x)^2-(1/2x-2/3x-3/4x)^2=?
答
{(1/2x+2/3x-3/4x)-(1/2x-2/3x-3/4x)}^2={1/2x+2/3x-3/4x-1/2x+2/3x+3/4x}^2=(4/3x)^2=8/3x
答
(1/2x+2/3x-3/4x)^2-(1/2x-2/3x-3/4x)^2
=(1/2x+2/3x-3/4x+1/2x-2/3x-3/4x)(1/2x+2/3x-3/4x-1/2x+2/3x+3/4x)
=(1/x-6/4x)(4/3x)
=4/3x^2-2/x^2
=-2/3x^2