已知2的x次方=3,y=log2(8/3)求x+2y的值答案可以写为带log的形式吗

问题描述:

已知2的x次方=3,y=log2(8/3)求x+2y的值
答案可以写为带log的形式吗

2^x=3→log(2)3=x,即x+2y=log(2)3+2log(2)8/3→log(2)3+log(2)64/9→log(2)3×64/9→log(2)64/3→2log(2)8/√3=8√3/3!望采纳,谢谢

已知2的x次方=3,y=log2(8/3)

log2 (3)=x
x+2y=log2 (3)+2log2(8/3)
=log2 (3)+log2(8/3)²
=log2 (3)+log2(64/9)
=log2 (3×64/9)
=log2(64/3)