因式分解2x^2+3xy-2y^2-4x+7y-6
问题描述：
因式分解2x^2+3xy-2y^2-4x+7y-6
答
2x^2+3xy-2y^2-4x+7y-6
=(2x-y)(x+2y)-3(2x-y)+2(x+2y)-6
=(2x-y+2)(x+2y-3)
答
双十字相乘法
原式=2x^2+(3y-4)x-(2y-3)(y-2)
=[2x-(y-2)][x+(2y-3)]
=(2x-y+2)(x+2y-3)