4/3+16/15+36/35+64/63+100/99+144/143=?

问题描述:

4/3+16/15+36/35+64/63+100/99+144/143=?


原式=1+1/3+1+1/15+1+1/35+1+1/63+1+1/99+1+1/143
=6+½[(1-1/3)+(1/3-1/5)+(1/5-1/7)+(1/7-1/9)+(1/9-1/11)+(1/11-1/13)]
=6+½[1-1/13】
=6+6/13
=6又6/13

=(1-1/3)+(1-1/3*5)+(1-1/5*7)+……+(1-1/11*13)
=6-[1/3+1/3*5+1/5*7+……+1/11*13]
=6-[(1/2)(1-1/3)+(1/2)(1/3-1/5)+(1/2)(1/5-1/7)+……(1/2)(1/11-1/13)]
=6-(1/2)(1-1/13)
=6-6/13
=72/13

原式=1+1/3+1+1/15+1+1/35+……+1+1/143
=6+1/2×(1-1/3+1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11+1/11-1/13)
=6+1/2×(1-1/13)
=6又6/13