递等式计算：8又3/41÷[0.375×（7-2又1/14×2又1/3+1/6）]
问题描述：
递等式计算：8又3/41÷[0.375×（7-2又1/14×2又1/3+1/6）]
答
8又3/41÷[0.375×（7-2又1/14×2又1/3+1/6）]
=8又3/41÷[0.375×（7-29/6+1/6）]
=8又3/41÷[0.375×（7-14/3]
=8又3/41÷[3/8×7/3]
=8又3/41÷7/8
=331/41×8/7
=2648/287
答
8又3/41÷[0.375×（7-2又1/14×2又1/3+1/6）]
=8又3/41÷[0.375×（7-29/14×7/3+1/6）]
=8又3/41÷[3/8×（7-29/6+1/6）]
=8又3/41÷(3/8×7/3)
=331/41÷7/8
=2648/287