化简x-1分之x+1-x2-1分之x2-2x÷x2-x-2/x2+2x+1

看不懂。。。。不如发图

（x+1)/(x-1)-(x²-2x)/(x²-1)÷(x²-x-2)/(x²+2x+1)
=(x+1)/(x-1)-[x(x-2)]/[x+1)(x-1)]×(x+1)²/[(x-2)(x+1)]
=(x+1)/(x-1)-x/(x-1)
=(x+1-x)/(x-1)
=1/(x-1)

原式=（x+1）/（x-1）-x(x-2)/(x+1)(x-1)÷(x-2)(x+1)/(x+1)²
=（x+1）/(x-1)-x/(x-1)
=(x+1-x)/(x-1)
=1/(x-1)


请好评

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