(-b+3a)-(a-b) (2x-5y)-(3x-5y+1) 2(2-7x)-3(6x+5) (-8x²+6x)-5(x²-5分之4x+5分之1) (3a²+2a-1)-2(a²-3a-5)
问题描述:
(-b+3a)-(a-b) (2x-5y)-(3x-5y+1) 2(2-7x)-3(6x+5)
(-8x²+6x)-5(x²-5分之4x+5分之1) (3a²+2a-1)-2(a²-3a-5)
答
(-b+3a)-(a-b)
=-b+3a-a+b
=2a
(2x-5y)-(3x-5y+1)
=2x-5y-3x+5y-1
=(2x-3x)-5y+5y-1
=-x-1
2(2-7x)-3(6x+5)
=4-14x-18x-15
=4-15-14x-18x
=-11-32x
(-8x²+6x)-5(x²-5分之4x+5分之1)
=-8x²+6x-5x²+4x-1
=-8x²-5x²+6x+4x-1
=-13x²+10x-1
(3a²+2a-1)-2(a²-3a-5)
=3a²+2a-1-2a²+6a+10
=(3a²-2a²)+(2a+6a)+(10-1)
=a²+8a+9